6y^2+11y-6=0

Solution for 6y^2+11y-6=0 equation:

6y^2+11y-6=0

a = 6; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·6·(-6)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{265}}{2*6}=\frac{-11-\sqrt{265}}{12}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{265}}{2*6}=\frac{-11+\sqrt{265}}{12}
$